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Big Ideas Math 2: 1.2 Piecewise Functions

(8 Questions)
58 viewed last edited 3 years ago
Monitoring Progress and Modeling with Mathematics
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Given the following functions. f(x) =\begin{cases} & 5x − 1 \text { , if x < -2} \\ & x + 3 \text{ , if x ≥ −2} \end{cases} g(x) =\begin{cases} & −x + 4 \text { , if x ≤ −1} \\ & 3 \text{ , if − 1 < x < 2} \\ & 2x − 5 \text{ , if x ≥ 2} \end{cases}
Find f(-2).
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1
Given the following functions. f(x) =\begin{cases} & 5x − 1 \text { , if x < -2} \\ & x + 3 \text{ , if x ≥ −2} \end{cases} g(x) =\begin{cases} & −x + 4 \text { , if x ≤ −1} \\ & 3 \text{ , if − 1 < x < 2} \\ & 2x − 5 \text{ , if x ≥ 2} \end{cases}
Find g(-4).
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1
Given the following functions. f(x) =\begin{cases} & 5x − 1 \text { , if x < -2} \\ & x + 3 \text{ , if x ≥ −2} \end{cases} g(x) =\begin{cases} & −x + 4 \text { , if x ≤ −1} \\ & 3 \text{ , if − 1 < x < 2} \\ & 2x − 5 \text{ , if x ≥ 2} \end{cases}
Find g(-1).
0
1
Given the following functions. f(x) =\begin{cases} & 5x − 1 \text { , if x < -2} \\ & x + 3 \text{ , if x ≥ −2} \end{cases} g(x) =\begin{cases} & −x + 4 \text { , if x ≤ −1} \\ & 3 \text{ , if − 1 < x < 2} \\ & 2x − 5 \text{ , if x ≥ 2} \end{cases}
Find g(1).
0
1
Given the following functions. f(x) =\begin{cases} & 5x − 1 \text { , if x < -2} \\ & x + 3 \text{ , if x ≥ −2} \end{cases} g(x) =\begin{cases} & −x + 4 \text { , if x ≤ −1} \\ & 3 \text{ , if − 1 < x < 2} \\ & 2x − 5 \text{ , if x ≥ 2} \end{cases}
Find f(0).
0
1
Given the following functions. f(x) =\begin{cases} & 5x − 1 \text { , if x < -2} \\ & x + 3 \text{ , if x ≥ −2} \end{cases} g(x) =\begin{cases} & −x + 4 \text { , if x ≤ −1} \\ & 3 \text{ , if − 1 < x < 2} \\ & 2x − 5 \text{ , if x ≥ 2} \end{cases}
Find g(5).
0
1
Given the following functions. f(x) =\begin{cases} & 5x − 1 \text { , if x < -2} \\ & x + 3 \text{ , if x ≥ −2} \end{cases} g(x) =\begin{cases} & −x + 4 \text { , if x ≤ −1} \\ & 3 \text{ , if − 1 < x < 2} \\ & 2x − 5 \text{ , if x ≥ 2} \end{cases}
Find f(5).
0
1
Given the following functions. f(x) =\begin{cases} & 5x − 1 \text { , if x < -2} \\ & x + 3 \text{ , if x ≥ −2} \end{cases} g(x) =\begin{cases} & −x + 4 \text { , if x ≤ −1} \\ & 3 \text{ , if − 1 < x < 2} \\ & 2x − 5 \text{ , if x ≥ 2} \end{cases}
Find f(-3).
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