Q

#### Geometric progression

(10 Questions)
11 viewed last edited 4 years ago
The geometric series are introduced in this lesson, as well as n'th term.
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The first term of a geometric sequence is 192 and the fifth term is 0.75. What is the common ratio?
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The fourth term of a geometric sequence is 27 and the seventh term is 1. What is the first term? Enter your answer as an integer.
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The first term of a geometric sequence is 5 and the sixth term is 160. What is the common ratio? Enter your answer as an integer.
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Is it a geometric sequence? If it is, find the first term and the common ratio" -\frac{1}{2}, \frac{1}{4}, -\frac{1}{8}, \frac{1} {16}, ......
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Given the terms a_{10} = \frac{3}{512} and a_{15} = \frac{3}{16384} of a geometric sequence, find the exact value of the term a_{30} of the sequence.
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Find the 10 th term of a geometric sequence if a_1 = 45 and the common ratio r = 0.2.
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The n-th term of a geometric sequence with initial value a and common ratio r is given by a_{n} = ar^{n-1} What is the ninth term of the geometric sequence 81, 27, 9, 3, ...?
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Match the following series \text { A) Infinite series } 1) a, ar, ar^2...........ar^{n-1} \text{ B) Finite series } 2) a, ar, ar^2 .......
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The general form of a geometric sequence is a, ar, ar^{2}, ar^{3}, ar^{4}....... Find the terms a_2, a_3, a_4 \text{ and } a_5 of a geometric sequence if a_1 = 10 and the common ratio r = - 1.
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Geometric sequence (geometric progression): It is a sequence such that any element after the first is obtained by multiplying the preceding element by a constant called the common ratio which is denoted by r. The common ratio (r) is obtained by dividing any term by the preceding term. r = \frac{a_2}{a_1} = \frac{a_3}{a_2}........= \frac{a_n}{a_{n-1}} where r = common ratio a_1 = first term, a_2 = second term, a_3 = third term a_{n-1} = the term before the n th term a_n = the n th term Which of the following is in geometric progression A) 10, 30, 90, 270, 810,....... B) 1, 2, 4, 8, 16, 32...........
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by Krishna