Q

Pre-calculus 21 - division of derivatives

(10 Questions)
1 viewed last edited 4 years ago
These questions illustrate the steps of the division of derivatives
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\frac {d}{dx}\frac{x+cos x}{tan x} = \frac{(1-sin x) tan x - (x+cos x)sec^2 x }{(tan x)^2}
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\frac {d}{dx}\frac {(x^2-1)^3}{x^2+1} = \frac{6x(x^2+1)(x^2-1)^2 - (x^2-1)^3(2x)}{(x^2+1)^2}
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See the attachment to Differentiate y= cot x
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Differentiate y=\frac{tan x}{cos x}
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Differentiate y=\frac{cot x}{sin x}.
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Find the y' for y=\frac{5sin x}{2x+cos x }
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Differentiate y= \frac{1+\ln x}{x^2- \ln x}
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Differentiate y=\frac{4x^3-7x}{5x^2+2}
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Differentiate y= \frac{x^2}{5x-2}.
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Take the attachment as a reference and Differentiate y=\frac{3}{x+2}
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by Krishna