0.5 moles of gas A and x moles of gas B exert a pressure of 200Pa - 0.5 moles of gas A and x moles of gas B exert a pressure of 200Pa in a volume of 10 meter-cube container at 1000K. Given R is gas constant in J K^(-1) (mol) ^(-1) then x is:

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0.5 moles of gas A and x moles of gas B exert a pressure of 200Pa jee main 2019

Deepti Jain (Parent, 12^th Grade)

Question as appeared in JEE Main 2019. The answer given by National Testing Agency's official answer key is Option (1). Please prove.

Sangeetha Pulapaka (last edited 4 years ago) (Expert, Educator @Qalaxia)

PV = nRT

200 × 10 = (0.5 + x) R × 1000

0.5 + x = \frac{2}{R}

x = \frac{4-R}{2R}

So the 4th option is correct. NTA has given answer 1. Which is not correct.

Mahesh Godavarti (last edited 4 years ago) (Expert, Founder @Qalaxia)

Here is a good reference that will help you arrive at the answer.