5.74 g of a substance occupies 1.2 cm^3 . Express its density by keeping the significant figures in view.

I found an answer from www.quora.com
How can we see the Crab Nebula, when it is only 1,001 years old ...
How do astronomers calculate the distance of a star that is 5.74 million light years ... Answered 3 years ago · Author has 1.2K answers and 545.6K answer views ... and 1,001 years ago people on Earth saw it happening in real time from our frame ... Andre Engels, M.A. Mathematics & Physics, University of Groningen ( 1996).
For more information, see How can we see the Crab Nebula, when it is only 1,001 years old ...
I found an answer from www.nasa.gov
Space Math V
additional challenges in the math and physical science curriculum in grades 9 ... findings and compete for the necessary funding for their space craft. ... km/s the distance is (2500-136)/412 = 5.74 megaparsecs ( or 18,700,000 light ... x (1.737 x 108)3 = 2.2 x 1025 cm3, so the density = 7.4 x 1025 grams / 2.2 x 1025 cm3.
For more information, see Space Math V
I found an answer from ncert.nic.in
Units & Measurement
number (or numerical measure) accompanied by a unit. Although the ... The base units for length, mass and time in these systems ... significant figures are 2, which is reliable and ... PHYSICS. 26. ◁ mass density is obtained by deviding mass by the volume of the substance. ... arithmetic operations can be understood from.
For more information, see Units & Measurement
Rounding off the Uncertain Digits
The preceding digit is left unchanged if the digit to be removed is less than 5
Example: 9.82 is rounded to 9.8.
The preceding digit is increased by one if the digit to be removed is greater than 5.
Example: 6.87 is rounded to 6.9
Read more: https://byjus.com/physics/error-significant-figures-rounding-off/
Given that
Substance mass m = 5.74 g
Volume of substance V = 1.2 cm^3
Formula of Density \rho = \frac{\text{mass}}{\text{volume}}
\rho = \frac{5.74}{1.2}
\rho = 4.78\bar{3}
Rounding to 4 significant digits
\rho = 4.8
Hence, density of the substance \rho = 4.8 g cm^{-3}