Mahesh Godavarti
1
1. Identify the relationship that ties acceleration, initial velocity, final velocity and displacement. That would be v_f^2 = v_i^2 + 2 \times a \times \Delta x .
2. Identify the given quantities in the relationship above. We have v_i = -13 m/s , x_i = 23 m , x_f = 18 m . Therefore, \Delta x = -5 m . Identify the acceleration which is acceleration due to gravity a = -10 m/s^2 .
3. Plug in the values to get v_f^2 = 13^2 + 2 \times 10 \times 5 = 269 m^2 /s^2
4. Solve for |v_f| = 16.4 m/s . Identify the sign which would be negative as the ball is falling downwards. Therefore, v_f = -16.4 m/s .

Therefore, the object will be falling at the rate of 16.4 m/s when it is 18m above the ground.

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Projectile height given time (video) | Khan Academy

We're just talking about when we get to this point right over here. So our final velocity is just 0 meters per second. And we're just going to divide that by 2. This will ...

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Kinematics - Wikipedia

Kinematics is a subfield of classical mechanics that describes the motion of points, bodies ... Then, using arguments from geometry, the position, velocity and acceleration of any ... Velocity Time physics graph ... of a body, which is used to derive equations of motion using either Newton's second law or Lagrange's equations.

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Equations for a falling body - Wikipedia

A set of equations describe the resultant trajectories when objects move owing to a constant ... This assumption is reasonable for objects falling to earth over the relatively ... During the first 0.05s the ball drops one unit of distance (about 12 mm ), ... of the Earth, the acceleration due to gravity g = 9.807 m/s2 (meters per second ...

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A ball of mass 8 kg is dropped from a height of 10 m. What is the ...

Once the object hit on the ground, height is zero, therefore no potential energy at ground level. We can rewrite above equation. Initial PE = Final KE. The mass m ...

For more information, see A ball of mass 8 kg is dropped from a height of 10 m. What is the ...