A 20kg shopping cart is traveling at 4m/s in a bumpy parking lot. The constant friction force on the cart is 4N. How far does the cart travel before coming a complete stop?

Kinetic energy is a form of energy that an entity or particle possesses due to its motion.
The relation between the object's mass and its speed.
KE = \frac{1}{2} mv^2
The work done is equal to the product of the applied force's magnitude and the distance traveled by the body.
W = f d
Step 1: Calculate the work done by the cart
Given that
Mass of the shopping cart m = 20kg
Shopping cart initial speed v_i = 4 m/s
Friction force f_f = 4N
Initial kinetic energy KE_i = \frac{1}{2}mv_i^2
KE_i = \frac{1}{2} (20kg)(4 m/s)^2
KE_i = 160 kg m^2/s^2
Thus, Initial kinetic energy KE_i = 160 joules
Since the cart will come to a complete stop, the final kinetic energy will be zero.
Final kinetic energy KE_f = 0
The change in kinetic energy is equivalent to work.
Change in kinetic energy \Delta KE=KE_f-KE_i
\Delta KE = 0 - 160
Work done W = \Delta KE = - 160 joules
"-" shows opposite direction of motion
Work done W = 160 joules
Step 2: Measure the cart's distance traveled until it came to a halt.
Work done W = f_f * d
160 joules = 4 N* d
d = \frac{160 joules}{4N}
d = 40 meters
Hence, The cart's total distance traveled before coming to a stop, d = 40 meters