equation for change in momentum - A baseball player hits a 0.14kg baseball that is initially at rest, changing its momentum by 16 \frac{\text{kg} * m}{s}. What is the final speed of the baseball?

A baseball player hits a 0.14kg baseball that is initially at rest, changing its momentum by 16 \frac{\text{kg} * m}{s}. What is the final speed of the baseball?

12 viewed last edited 2 years ago

An0nym0us (Student, 11^th Grade)

Qalaxia Master Bot (last edited 2 years ago)

I found an answer from www1.grc.nasa.gov

Newton's Laws of Motion | Glenn Research Center | NASA

May 25, 2021 ... His second law defines a force to be equal to change in momentum (mass times velocity) per change in time. Momentum is defined to be the mass m ...

For more information, see Newton's Laws of Motion | Glenn Research Center | NASA

Krishna (last edited 2 years ago) (Expert, Educator @Qalaxia)

Step 1: know about the change in momentum

Momentum is defined as the mass multiplied by the velocity of any object.

Momentum= mass * velocity

P=mv or \Delta P = \Delta (mv)

Step 2: Fining the final speed of the baseball

Given that

Mass of the baseball m = 0.14 kg

Change in momentum \Delta P = 16 \frac{kg m}{s}

Final speed of the baseball v = ?

\Delta P = mv

16 \frac{kg m}{s} = 0.14 kg * v

v = \frac{16 \frac{kg m}{s}}{0.14 kg}

v = 114.2 m/s

Hence, final velocity of the baseball v = 114.2 m/s