Krishna
0

Step 1: Analyse the given question. Draw a figure from the given information.

              Given that:

                  The boat cross a river

                  The angle between the boat and bank = 60\degree


                      


                    From the figure:

                         AB is a bank of the river    

                         Boat starts at A.                         

                         Angle between the bank of the river and way of the boat \angle CAB = 60\degree.

                         Traveled distance AC = 600 m

                         Determine the width of the river BC = ?


Step 2: Select the appropriate trigonometric ratio to find the width of the river.  

                 We need to find the width of the river (opposite side)


                                So, take \sin\ A=\frac{opposite\ side}{hypotenuse}


                                              \sin60\degree=\frac{BC}{AC}=\frac{BC}{600}


                                                      \frac{\sqrt{3}}{2}=\frac{BC}{600}.    (Since \sin60\degree=\frac{\sqrt{3}}{2})


                                                    BC=\frac{600\sqrt{3}}{2})


                                                     BC = 300\sqrt{3}


                                        Hence, the width of the river   BC = 300\sqrt{3}

Pendyala Varsha
0
Thank u 😊😊
Anonymous
0
Where is the location of the boat and what is step 1?
Mahesh Godavarti
0
The location of the boat is A. And Step 1 is to identify all the given information.
Mahesh Godavarti
0
The answer has been edited to correctly identify Step 1.