Krishna
0

Step 1: Analyse the given question. Draw a figure from the given information.

Given that:

The boat cross a river

The angle between the boat and bank = 60\degree

From the figure:

AB is a bank of the river

Boat starts at A.

Angle between the bank of the river and way of the boat \angle CAB = 60\degree.

Traveled distance AC = 600 m

Determine the width of the river BC = ?

Step 2: Select the appropriate trigonometric ratio to find the width of the river.

We need to find the width of the river (opposite side)

So, take \sin\ A=\frac{opposite\ side}{hypotenuse}

\sin60\degree=\frac{BC}{AC}=\frac{BC}{600}

\frac{\sqrt{3}}{2}=\frac{BC}{600}.    (Since \sin60\degree=\frac{\sqrt{3}}{2})

BC=\frac{600\sqrt{3}}{2})

BC = 300\sqrt{3}

Hence, the width of the river   BC = 300\sqrt{3}

Pendyala Varsha
0
Thank u ðŸ˜ŠðŸ˜Š
Anonymous
0
Where is the location of the boat and what is step 1?
Mahesh Godavarti
0
The location of the boat is A. And Step 1 is to identify all the given information.
Mahesh Godavarti
0
The answer has been edited to correctly identify Step 1.