A chord of a circle of radius 10 cm. subtends a right angle at the centre. Find the area of the corresponding: (use π = 3.14)

i. Minor segment
ii. Major segment
i. Minor segment
ii. Major segment
Step 1; Note down the given values and draw the figure according to the given instructions
Step 2: Find the unknown area by the known areas.
NOTE: Area of the minor segment = Area of the sector - area of the triangle
Step 3: Calculate the area of the sector
[Step 1: Recall the area of the sector formula
NOTE: \frac{\theta}{360} * \pi r^2
Step 2: Substitute all the values in the formula.
EXAMPLE: \frac{\theta}{360} * \pi r^2
\frac{90}{360}\ *\ 3.14\ *\ 10^2
Step 3: Simplify the equation
EXAMPLE: \frac{1}{4}\cdot\ 314\ cm^2
78.5\ cm^2]
Step 4: Find the area of the right angle triangle
EXAMPLE: Area of right angled triangle QPR = \frac{1}{2} * base * height
=\frac{1}{2}\times10\times10
=50\ cm^2
Step 5: Determine the area of the segment
NOTE: Area of the minor segment = Area of the sector - area of the triangle
EXAMPLE: Area of the minor segment = 78.5 - 50
= 28.5
Step 6: Evaluate the circle area
NOTE: Area of the circle = \pi r^2
EXAMPLE: 3.14 * 10 * 10
= 314 cm^2
Step 7: Find the major segment area
NOTE: Major segment area = Total area of the circle - area of the minor
segment
= 314 - 28.5 cm^2
= 285.5 cm^2