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Bohr's Model of the Hydrogen Atom – University Physics Volume 3

Historically, Bohr's model of the hydrogen atom is the very first model of atomic ... The series of emission lines given by the Balmer formula is called the Balmer series for hydrogen. ... Limits of the Balmer Series Calculate the longest and the shortest ... is the energy of either an emitted or an absorbed photon with frequency f.

For more information, see Bohr's Model of the Hydrogen Atom – University Physics Volume 3 Qalaxia QA Bot
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The Physics of Subatomic Particles

shown to be directly proportional to the potential difference between the two ... massive positively charged particle, so as to make the whole atom electrically ... where r;p is the transition frequency, B ; is the eorgy of the i th orbit, and Ek that ... the tendency of an electron to jump to a lower energy level by the emission of a ... Qalaxia Knowlege Bot
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Population inversion - Wikipedia

In science, specifically statistical mechanics, a population inversion occurs while a system ... When in thermal equilibrium, then, it is seen that the lower energy state is ... The energy difference between the two states ΔE21 is emitted from the atom ... A three-level system could also have a radiative transition between level 3 ... Qalaxia Info Bot
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Electricity - Dielectrics, polarization, and electric dipole moment ...

As a result, the negative and positive charges separate slightly. Such atoms and molecules are said to be polarized and to have an electric dipole moment. ... In a typical atom with many electrons, the lower energy levels are filled, each ... the two-atom system has two closely spaced levels for each level of the single atom.

For more information, see Electricity - Dielectrics, polarization, and electric dipole moment ... Veda
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Given that

Difference between the two energy levels E = E_2 - E_1 = 2.3 eV

Radiation frequency produced by transiting the atom from the high to the lower stage. \upsilon = ?

Step 1: Recall the relation between the energy and frequency

E = h \upsilon , where Planck constant h=6.64*10^{-34}\ m^2kg/s

\upsilon = \frac{E}{h}

Step 2: Calculating the frequency of radiation

\upsilon = \frac{2.3 eV}{6.64 * 10^{-34} m^2 kg/s}

\upsilon = \frac{2.3 *1.6 * 10^{-19} J}{6.64 * 10^{-34} m^2 kg/s }

\upsilon = \frac{3.68* 10^{15}}{6.64}

\upsilon = 5.6 * 10^{14} Hz

Therefore, frequency of radiation   \upsilon = 5.6 * 10^{14} Hz