#### A jar contains 5 red,7 green,6 orange and 5 blue balls.If a single ball is drawn from the jar, what is the probability of choosing-

- One red ball?
- One green ball?
- One blue ball?
- One non red ball?
- One orange ball?

RejuvenatedAfricanBuffalo

0

- One red ball?
- One green ball?
- One blue ball?
- One non red ball?
- One orange ball?

Sangeetha Pulapaka

1

Hi ** RAB,**

I asuume you do know what probability means. Just a quick recall though, Probability is the possibility of an event happening. This is best defined by the formula P(E) = Number of outcomes favourable to the event / Total number of possible outcomes.

The total number of possible outcomes is known when we calculate the total number of balls in the jar which is 5+7+6+5 = 23 balls

If the event is pulling out one red ball, then the probability of this happening is

P( Probability of pulling a red ball)/ Total number of balls = 5/23

P( Probability of pulling out one green ball)/ Total number of balls = 7/23

P( Probability of pulling out one blue ball)/ Total number of balls = 5/23

P(Probability of pulling out one orange ball) / Total number of balls = 6/23

Now the probability of an event not happening is known as the complement of an event. If the probability of an event happening is P(E), then the probability of an event not happening can be represented as P(E').

There is another formula, we can use here. It is

P(E) + P(E') = 1

Now we calculate the probability of not getting a red ball

P(E') = 1 - P(E) = 1- 5/23 (Since the probability of getting a red ball is 5/23

= 18/23

I hope this answers your question. Bye!

RejuvenatedAfricanBuffalo

0

Thank you very much Sangeetha

Sangeetha Pulapaka

0

You are most welcome RAB!