Krishna
0

Step 1: Analyse the given data.  

                  Key words to understand the question.

  •   A line joining the eye of the observer and object viewed by the observer. This line is called “line of sight”. 
  • The line of sight is above the horizontal line and angle between the line of sight and the horizontal line is called angle of elevation.
  • The line of sight is below the horizontal line and angle between the line of sight and the horizontal line is called angle of depression.


Step 2:  When we want to solve the problems of heights and distances, we should consider the following:

  1. All the objects such as towers, trees, buildings, ships, mountains etc. shall be considered as linear for mathematical convenience.
  2. The angle of elevation or angle of depression is considered with reference to the horizontal line.
  3. The height of the observer is neglected, if it is not given in the problem.


Step 3: According to the given data make a imaginary figure.

          GIVEN: A large balloon  has been tied with a rope and it is floating in the air. 

                      Angle of elevation \theta_1

                      Angle of depression \theta_2

                     The height of the building is h feet.

    Skill 1;  First make a building(DE) of height h and Assume a balloon with a

                  rope(AC) floating in the air.  


    Skill 2: Draw a horizontal line (DB) from the top of the building to the balloon.


    Skill 3:  Make a angle of elevation and angle of depression from the top of the

                building  

                      

                              

              

Rupesh Nothing
0
What is the height between the foot of the rope and the balloon
Krishna
0
Hai Rupesh.. From the figure, Distance(height) between the rope's foot and the balloon = AC AC = AB + BC AB = DE height of the building = h. \because ABDE \text{ is a rectangle } The BC length can be calculated using trigonometric ratios, but we have to know the values of the \theta_1 and any length of the triangle BCD. \tan \theta_1 = \frac{BC}{BD} BC = BD \tan \theta_1 Hence, the height between the foot of the rope and the balloon AC = h + BD \tan \theta_1