knowledge of pythagoras theorem - A man wishes to estimate the distance of a nearby tower from him. He stands at a point A in front of the tower C and spots a very distant object O in line with AC. He then walks perpendicular to AC up to B, a distance of 100 m, and looks at O and C again. Since O is very distant, the direction BO is practically the same as AO; but he finds the line of sight of C shifted from the original line of sight by an angle \theta =. 40\degree (θ is known as ‘parallax’) estimate the distance of the tower C from his original position A.

A man wishes to estimate the distance of a nearby tower from him. He stands at a point A in front of the tower C and spots a very distant object O in line with AC. He then walks perpendicular to AC up to B, a distance of 100 m, and looks at O and C again. Since O is very distant, the direction BO is practically the same as AO; but he finds the line of sight of C shifted from the original line of sight by an angle \theta =. 40\degree (θ is known as ‘parallax’) estimate the distance of the tower C from his original position A.

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Anonym0us (Student, UG1 Grade)

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I found an answer from byjus.com

Pythagoras Theorem (Formula, Proof and Examples)

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Sniper - Wikipedia

A sniper is a military/paramilitary marksman who engages targets from positions of concealment or at distances exceeding the target's detection capabilities.

For more information, see Sniper - Wikipedia

Guru Nanak (last edited 2 years ago) (Student, UG2 Grade)

Step 1: Make a figure from the given information

Step 2: Finding the distance between the position A and tower C

Given that

Parallax angle \theta = 40\degree

Distance AB = 100 m

From the figure

\triangle ABC is a right triangle

Trigonometric ratio \tan \theta = \frac{AB}{AC}

Distance between the position A and tower C = AC

AC = \frac{AB}{\tan \theta }

AC = \frac{100}{\tan 40\degree}

AC = \frac{100}{0.8391} = 119 m

Hence, distance between the position A and tower C, AC = 119 m