#### A mercury drop of radius 1 cm is sprayed into 10^6 drops of equal size. The energy expressed in joule is (surface tension of Mercury is 460 * 10^{-3} N/m)

I found this to be a very interesting question on the concept of surface tension...

Anonymous

1

I found this to be a very interesting question on the concept of surface tension...

Krishna

0

Surface tension of a liquid is measured as force acting per length

Surface tension T = \frac{force(F)}{area(A)}.....................(1)

You can calculate force F = T * A

Step 1: In the question they given

NOTE: Radius = 1 cm

1 cm = 10^{-2}

Surface tension of mercury = 460 * 10^{-3}

We have to calculate the energy

FORMULA: Force F = T * [math] 4 \pi r^2 [n^(\frac{1}{3}) -1)][/math]

Step 2: Substitute the known values in the formula

Force F = [math] 460 * 10^{-3} * 4 \pi (10^{-2})^2 [(10^6)^(\frac{1}{3}) -1)][/math]

F = [math] 460 * 12..56 * 10^{-3} * 10^{-4} * [100 -1][/math]

F = 46 * 10 *12.56 * 10^{-7} (99)

F = 57,198.24 * 10^{-6}

F = 0.057 joule

Vamsi Krishna

0

Thanks