The relative error in a physical quantity raised to the power k is equal to k times the individual quantity's relative error.
Z = \frac{A^p B^q}{C^r}
\frac{\Delta Z}{Z} = p \frac{\Delta A}{A} + q \frac{\Delta B}{B} + r \frac{\Delta C}{C}
Percentage error = \frac{\text{ absolute error }}{\text{ measurement }} 100%
Percentage error in the quantity P = \frac{\Delta P}{P} * 100
Given that
Physical quantity P = \frac{a^3 b^3}{\sqrt{c}d} , where, a, b, c and d are observables
The percentage errors of observables \frac{\Delta a}{a}* 100 = 1%
\frac{\Delta b}{b} * 100 = 3%
\frac{\Delta c}{c} * 100 = 4%
\frac{\Delta d}{d} * 100= 2%
Step 1: Finding the percentage error
Physical quantity, P = \frac{a^3 b^3}{\sqrt{c}d}
P = \frac{a^3 b^3}{c^{\frac{1}{2}}d}
Error when a calculated quantity is raised to a power
Relative error \frac{\Delta P}{P} = 3 \frac{\Delta a}{a} + 3\frac{\Delta b}{b} + \frac{1}{2} \frac{\Delta c}{c} + \frac{\Delta d}{d}
Percentage error \frac{\Delta P}{P} * 100 = 3 \frac{\Delta a}{a} * 100 + 3 \frac{\Delta b}{b} * 100 + \frac{1}{2} \frac{\Delta c}{c} * 100 + \frac{\Delta d}{d} * 100
\frac{\Delta P}{P} * 100 = = 3 * 1% + 3 * 3% + \frac{1}{2} 4% + 2%
= 3 % + 9 % + 2% + 2%
= 13%
Hence, Percentage error of the quantity, P = 13%
Given value of the quantity P, = 3.763
Rounding the quantity P = 3.8