Krishna
0

Step 1: Recall the relation between the areas of the similar triangles.

THEOREM: The ratio of the areas of two similar triangles is equal to the

ratio of the squares of their corresponding sides

\frac{Area \triangle ABC}{Area \triangle DEF} = (\frac{AB}{DE})^2 = (\frac{BC}{EF})^2 = (\frac{CA}{FD})^2

Step 2: Substitute all the known values in the theorem

EXAMPLE:   \frac{Area \triangle ABC}{Area \triangle DEF} =(\frac{BC}{EF})^2

= \frac{54}{Area\ of\ \triangle DEF}=(\frac{3}{4})^2

Step 3: Simplify for the unknown value

EXAMPLE:  Area\ of\ the\ \triangle DEF\ =\frac{16}{9}*\ 54

Area of the \triangle DEF = 16 * 6

Area of the \triangle DEF = 96 cm^2