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An alligator crawls 15 m to the left with an average velocity of - 2.5m/s. How many seconds did the alligator crawl? Answer using a coordinate system where rightward is positive.
10 viewed last edited 1 year ago
An0nym0us
0
Krishna
0

Calculating the ratio of the total distance travelled by the body to the time taken to cover that distance obtains the average speed.

\text{ Average speed } = \frac{\text{Total distance}}{\text{ Total time }}

        or

v_{avg} = \frac{d}{t}

Step 1: Rewrite the time equation using the average speed formula

Given that

Average velocity, v_{avg}=-2.5\ m/s

Distance alligator crawls left side d = - 15 m ?  

Time taken to crawl t = ?

v_{avg} = \frac{d}{t}

t=\frac{d}{v_{avg}}

Step 2: Calculate the total time taken to crawl.

t=\frac{d}{v_{avg}}

t = \frac{- 15 m}{-2.5m/s}

t = 6 sec

Hence, total time alligator crawl, t=6\ \sec