An isosceles trapezoid of height,4ft and bases 6ft and 12 ft with the smaller base lying on the surface

Do you want to find the area here?
The area of an isosceles trapezoid is given by the formula
area of isosceles trapezoid = (sum of parallel sides ÷ 2) × height
The bases height are 6 ft and 12 ft respectively which are parallel to each other,
The sum of the parallel sides = 6 ft + 12 ft = 18 ft.
height = 4ft
So plug these in the above formula to get
area of an isosceles trapezoid = \frac{18 ft}{2} \times 4 ft = 36 ft^{2}
I found an answer from math.stackexchange.com
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