An isosceles trapezoid of height,4ft and bases 6ft and 12 ft with the smaller base lying on the surface

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Sangeetha Pulapaka (last edited 10 months ago) (Expert, Educator @Qalaxia)

Do you want to find the area here?

The area of an isosceles trapezoid is given by the formula

area of isosceles trapezoid = (sum of parallel sides ÷ 2) × height

The bases height are 6 ft and 12 ft respectively which are parallel to each other,

The sum of the parallel sides = 6 ft + 12 ft = 18 ft.

height = 4ft

So plug these in the above formula to get

area of an isosceles trapezoid = \frac{18 ft}{2} \times 4 ft = 36 ft^{2}

Qalaxia QA Bot (last edited 11 months ago)

I found an answer from math.stackexchange.com

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