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Fission | Physics

Fission is the opposite of fusion and releases energy only when heavy nuclei are split. ... The amount of energy per fission reaction can be large, even by nuclear standards. ... about 1 MeV per nucleon, or approximately 240 MeV per fission, is released. ... given the atomic masses to be m(238U) = 238.050784 u, m(95Sr) ...

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Thorium - Wikipedia

Thorium is a weakly radioactive metallic chemical element with the symbol Th and atomic ... 232Th is one of the three nuclides beyond bismuth (the other two beingU ... Thorium nuclei are susceptible to alpha decay because the strong nuclear force ... 232Th also very occasionally undergoes spontaneous fission rather than ...

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What cool things can be built with mathematics? Physics has the ...

Physics has the quantum computer and a nuclear fusion reactor while math just has a limestone pyramid. Controversially, I'll go with.... Physics. Firstly, everyone  ...

For more information, see What cool things can be built with mathematics? Physics has the ...

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https://www.britannica.com/animal/Norwegian-elkhound 2021-03-29 ...

Nuclear fission is used in nuclear reactors to produce energy for electrical power ... A “closed loop” nuclear fuel cycle, showing the reprocessing of uranium-235 and ... /nuclear-fusion/Energy-released-in-fusion-reactions 2021-03-29 monthly 1.0 ... A test of a U.S. thermonuclear weapon (hydrogen bomb) at Enewetak atoll in ...

Veda
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a)

Mass of hydrogen m = 1.0 kg

Nuclear reaction: 4 ^{1}_{1} H \rightarrow ^{4}_{2} He

Energy released during the four hydrogen nuclei fuse to form a helium nucleus = 26 MeV

atomic mass of hydrogen = 4

Step 1:Number of atoms in the given mass of the substance

If 1g of hydrogen contains 6.023 * 10^{23} atoms

then, number of atoms in 1kg hydrogen = \frac{6.023 * 10^{23} * 1000}{4}

Step 2: Calculate the energy released in the nuclear fusion

The energy produced by the fusion of 1kg hydrogen

E = \text{number of atoms * energy/4nuclei } = \frac{6.023 * 10^{23} * 1000}{4} * 26 MeV

E = 39.149 * 10^{26} MeV

Energy released in 1kg hydrogen E_H = 39.149 * 10^{26} MeV

b)

Mass of Uranium [math] m = 1.0 kg [/math

The energy emitted by a single uranium nucleus fission is 200 MeV.

atomic mass of uranium 235 = 235

Step 1:Number of atoms in the given mass of the substance

If 1g of Uranium contains 6.023 * 10^{23}

then, number of atoms in 1kg  Uranium = \frac{6.023 * 10^{23} * 1000}{235}

Step 2: Calculate the energy released in the nuclear fusion

The energy produced by the fusion of 1kg Uranium

E = \text{number of atoms * energy/nuclei } = \frac{6.023 * 10^{23} * 1000}{235} * 200 MeV

E = 5.106 * 10^{26} MeV

Energy released in 1kg uranium E_U = 5.106 * 10^{26} MeV

Comparison of energies released

E_H=39.149*10^{26} MeV  and E_U = 5.106 * 10^{26} MeV

\frac{E_H}{E_U} = \frac{39.149 * 10^{26}}{5.106 * 10^{26}}

\frac{E_H}{E_U} =7.69 \approx 8

E_H = 8 * E_U

As a result, the energy produced in the fusion of one kilogram of hydrogen is approximately eight times that released in the fission of one kilogram of uranium.