Step 1: Examine the given figure  

Step 2: Identify the parallel lines and transversals in the given figure

            NOTE:  AD || BC and AB || DC

                          BE is a transversal

Step 3: Locate the equal angles in the figure

            NOTE:  ∠ABE = ∠CFB (Alternate angles)

                        ∠AEB = ∠CBF (Alternate angles)

Step 4: Prove that \triangle ABE and \triangle CFE are similar

          NOTE:  According to AAA theorem we can say \triangle ABE and \triangle CFE

          are similar

          Hence; Δ ABE ∼ Δ CFB proved (AAA criterion)