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a)

Formula volume of the cube = x^3 cubic units

Given that, side of the cube x = 1cm

Volume of the cube = 1 cm * 1 cm * 1 cm = 1 cm^3   

Hence, cube volume V = 1 cm^3 = 1* 10^{-6} m^3

b)

Radius of the cylinder r = 2.0 cm

Height of the cylinder h = 10.0 cm  

Surface area of the cylinder S.A =  Curved Surface + Area of Circular bases

S.A = 2\pi r(h + r) square units

Plug in the given values in the formula

S.A = 2 * 3.14 * 2.0(10 + 2.0)

S.A = 150.72 cm^2

S.A = 15072 mm^2                \because 1 cm = 10 mm

c)

Speed v = 18 km/h = 18* \frac{5}{18} m/s = 5 m/s      \because 1 m/s = \frac{1000}{60* 60} = \frac{5}{18} m/s   

Time t = 1 seconds

\text{ speed } = \frac{\text{ Distance }}{\text{ time }}

\text{ Distance } = speed * time = 5 m/s * 1 s = 5 m

Thus, distance covered d = 5 m

d)

Lead relative density RD = 11. 3   

Density of lead \rho = ?

Density of the water(reference) \rho_w = 1 g/cm^3 = 1000 kg/m^3

Formula: \text{relative density substance} = \frac{\text{ density of substance }}{\text{density of reference }}

\text{ density of substance } = \text{ relative density substance } * \text{ density of reference }

\text{ density of substance } = 11.3 * 1000 kg/m^3

\text{ density of substance } = 11300 kg/m^3