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Weight, mass and gravitational field strength - Newton's Laws ...


Example. An apple has a mass of 100 g. Calculate its weight on Earth (g = 10 N/ kg). 100 g = 100 ÷ 1000 = 0.1 kg.


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A water tank is 3 m long, 2 m wide and 1 m high. How many litres ...


Given; length=3m, breadth=2m, height=1m. Since volume of a regular cuboid= length×breadth×height So, volume=3m×2m×1m Volume=6m^3 Now, since ...


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CBSE NCERT Solution for Class 11 - Physics - Units and ...


CBSE Ncert Solution for Class 11 - Physics - Units and Measurements. ... (a) The volume of a cube of side 1 cm is equal to .....m3 ... The total surface area of a cylinder of radius r and height h is: ... Given Time, t = 1sec. ... Suppose we employ a system of units in which the unit of mass equals α kg, the unit of length equals β m ...


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The Bicycle Problem That Nearly Broke Mathematics - Scientific ...


Jul 20, 2016 ... Jim Papadopoulos has spent a lifetime pondering the maths of bikes in motion. ... He could never ride a bike without pondering the mathematical mysteries that it contained. ... Why must one initially steer right in order to lean and turn left? ... anywhere from 5 centimetres to 10 centimetres behind the steering ...


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Teja
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a)

Formula volume of the cube = x^3 cubic units

Given that, side of the cube x = 1cm

Volume of the cube = 1 cm * 1 cm * 1 cm = 1 cm^3   

Hence, cube volume V = 1 cm^3 = 1* 10^{-6} m^3


b)

Radius of the cylinder r = 2.0 cm

Height of the cylinder h = 10.0 cm  

Surface area of the cylinder S.A =  Curved Surface + Area of Circular bases

S.A = 2\pi r(h + r) square units

Plug in the given values in the formula

S.A = 2 * 3.14 * 2.0(10 + 2.0)

S.A = 150.72 cm^2

S.A = 15072 mm^2                \because 1 cm = 10 mm


c)

Speed v = 18 km/h = 18* \frac{5}{18} m/s = 5 m/s      \because 1 m/s = \frac{1000}{60* 60} = \frac{5}{18} m/s   

Time t = 1 seconds

\text{ speed } = \frac{\text{ Distance }}{\text{ time }}

\text{ Distance } = speed * time = 5 m/s * 1 s = 5 m

Thus, distance covered d = 5 m


d)

Lead relative density RD = 11. 3   

Density of lead \rho = ?

Density of the water(reference) \rho_w = 1 g/cm^3 = 1000 kg/m^3

Formula: \text{relative density substance} = \frac{\text{ density of substance }}{\text{density of reference }}

\text{ density of substance } = \text{ relative density substance } * \text{ density of reference }

\text{ density of substance } = 11.3 * 1000 kg/m^3

\text{ density of substance } = 11300 kg/m^3