Krishna
0

Method 1:

Step 1: Note down the given points as well as assign these points with the variables

            EXAMPLE: ( 7, 4 ) assign this point with (x_1, y_1)

                              ( 2, 0 ) assign this point with (x_2,y_2)

                      ................etc

Step 2: Calculate gradient or slope(m) from two points

            FORMULA: \frac{y-change}{x-change},

                            or \frac{y_2 - y_1}{x_2 - x_1}


            EXAMPLE: Slope of A(7, 4) and B(2, 0 )

                              \frac{4-0}{7-2} = \frac{4}{5}

Step 3: Substitute either values slope(m) and any one point into the equation of a straight line.

            FORMULA: Equation of a straight line

                               y - y_1 = m(x - x_1)

                            Where m = slope and ( x_1, y_1) = any point


            EXAMPLE: I took (2, 0) as a point and m = \frac{4}{5}

                                         y - 0 = \frac{4}{5} ( x - 2)

                                            5y = 4x - 8


Step 4: Simplify and make the equation in the form of Ax + By + C =0


Method 2:

Step 1: Note down the given points as well as assign these points with the variables

            EXAMPLE: ( 7, 4 ) assign this point with (x_1, y_1)

                              ( 2, 0 ) assign this point with (x_2, y_3)

                                ................etc

Step 2: Substitute either given points in the formula.

          FORMULA:

(y_1-y_2)x+\left(x_2-x_1)y+(x_1y_2-x_2y_1)\right)



Step 3: Simplify and make the equation in the form of Ax+ By + C =0

Qalaxia Info Bot
0

I found an answer from www.khanacademy.com

Writing equations of perpendicular lines | Analytic geometry (video ...


Given line A and point P, Sal finds the equation of the line perpendicular to A that passes ... Practice: Write equations of parallel & perpendicular lines ... My two points for my second line are now (2,6) (0,5). By ... So, I have the answer BY USING A GRAPH. ... Do this by doing what you did before--find your m and b values.


For more information, see Writing equations of perpendicular lines | Analytic geometry (video ...

Qalaxia QA Bot
0

I found an answer from www.quora.com

How to find the equation of the perpendicular bisector of AB, where ...


Next find the mid point of AB, which is C [(3–3)/2, (6+4)/2] or (0,5). Next find the equation of line AB, which is (x-3... ... Ad by The Motley Fool ... Answered December 29, 2017 · Author has 24K answers and 11.4M answer ... What is the equation of the perpendicular bisector of the segment joining points A (2, 2) and B (6, 8)?.


For more information, see How to find the equation of the perpendicular bisector of AB, where ...

Qalaxia Master Bot
0

I found an answer from www.corestandards.org

High School: Geometry | Common Core State Standards Initiative


Euclidean geometry is characterized most ... through a point not on a given line there is exactly one parallel line. (Spherical geometry, in contrast, has no parallel lines.) During high school, students begin to formalize ... coordinates and geometric points allows methods ...


For more information, see High School: Geometry | Common Core State Standards Initiative

Qalaxia Knowlege Bot
0

I found an answer from en.wikipedia.org

Linear equation - Wikipedia


One variable[edit]. Frequently the term linear equation refers implicitly to the case of just one variable. In this case, the equation can be put in the form. a x + b = 0 ...


For more information, see Linear equation - Wikipedia