Method 1:

Step 1: Note down the given points as well as assign these points with the variables

EXAMPLE: ( 7, 4 ) assign this point with (x_1, y_1)

( 2, 0 ) assign this point with (x_2,y_2)

................etc

Step 2: Calculate gradient or slope(m) from two points

FORMULA: \frac{y-change}{x-change},

or \frac{y_2 - y_1}{x_2 - x_1}

EXAMPLE: Slope of A(7, 4) and B(2, 0 )

\frac{4-0}{7-2} = \frac{4}{5}

Step 3: Substitute either values slope(m) and any one point into the equation of a straight line.

FORMULA: Equation of a straight line

y - y_1 = m(x - x_1)

Where m = slope and ( x_1, y_1) = any point

EXAMPLE: I took (2, 0) as a point and m = \frac{4}{5}

y - 0 = \frac{4}{5} ( x - 2)

5y = 4x - 8

Step 4: Simplify and make the equation in the form of Ax + By + C =0

Method 2:

Step 1: Note down the given points as well as assign these points with the variables

EXAMPLE: ( 7, 4 ) assign this point with (x_1, y_1)

( 2, 0 ) assign this point with (x_2, y_3)

................etc

Step 2: Substitute either given points in the formula.

FORMULA:

(y_1-y_2)x+\left(x_2-x_1)y+(x_1y_2-x_2y_1)\right)

Step 3: Simplify and make the equation in the form of Ax+ By + C =0

I found an answer from www.khanacademy.com

Writing **equations** of perpendicular **lines** | Analytic geometry (video ...

Given **line** A and point P, Sal finds the **equation** of the **line** perpendicular to A that
passes ... Practice: Write **equations** of parallel **&** perpendicular **lines** ... My two
points **for** my second **line** are now (**2**,6) (**0**,5). **By** ... So, I have the **answer BY**
USING A GRAPH. ... Do this **by** doing what **you** did before--**find your** m and **b**
values.

For more information, see Writing **equations** of perpendicular **lines** | Analytic geometry (video ...

I found an answer from www.quora.com

How to **find** the **equation** of the perpendicular bisector of AB, where ...

Next **find** the mid point of AB, which is **C** [(3–3)/**2**, (6+**4**)/**2**] or (**0**,5). Next **find** the
**equation** of **line** AB, which is (x-3... ... Ad **by** The Motley Fool ... **Answered**
December 29, 2017 · Author has 24K **answers** and 11.4M **answer** ... What is the
**equation** of the perpendicular bisector of the segment **joining** points A (**2**, **2**) and
**B** (6, 8)?.

For more information, see How to **find** the **equation** of the perpendicular bisector of AB, where ...

I found an answer from www.corestandards.org

**High School**: **Geometry** | Common Core State Standards Initiative

Euclidean **geometry** is characterized most ... through a **point** not on a **given line**
there is exactly one parallel **line**. (Spherical **geometry**, in contrast, has no parallel
**lines**.) During **high school**, students begin to formalize ... **coordinates** and
**geometric points** allows methods ...

For more information, see **High School**: **Geometry** | Common Core State Standards Initiative

I found an answer from en.wikipedia.org

Linear **equation** - Wikipedia

One variable[edit]. Frequently the term linear **equation** refers implicitly to the case
of just one variable. In this case, the **equation** can be put in the **form**. a x + **b** = **0** ...

For more information, see Linear **equation** - Wikipedia