Find the area of the circle inscribed to an isosceles triangle of base 10 units and lateral side 12 units.

Step 1: Recall the formula to find the radius of the circle inscribed to an isosceles triangle.
FORMULA : r = \frac{b}{2} \sqrt{\frac{2a - b}{2a + b}}
Where the lateral side a, and base b of the isosceles triangle
Step 2: Plug in the values of lateral side and base into the formula
EXAMPLE: r=\frac{10}{2}\sqrt{\frac{\left(2*12\right)-10}{\left(2*12\right)+10}}
r = 5 \sqrt{\frac{14}{34}}
r = 5 * 0.645
r = 3.2
Step 3: Recall the area formula of the circle
Area of the circle = \pi r^2
Where r - radius of the circle
Step 4: Substitute the radius values in the area of the circle formula
EXAMPLE: Area = \pi r^2
= \pi (3.2)^2
= \pi (10.56)
= 33.188