 Krishna
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Step 1: Note down the given values and examine the given figure

Step  2: Find the unknown area by the known areas.

NOTE: Area of the segments shaded = Area of sector OQPR - Area of triangle PQR

Step 3: Make sure is it a right angle triangle or not

NOTE: Since QR is diameter, ∠QPR = 90° (Angle in a semicircle)

Step 4: Calculate the diameter of the circle by using the Pythagoras theorem

EXAMPLE: Using Pythagoras Theorem In ∆QPR,

QR^2 = PQ^2 + PR^2

=   24^2 + 7^2

= 576 + 49

= 625

Diameter  QR = 625 = 25 cm.

Step 5: Calculate the radius of the circle

NOTE: Diameter = 2 * radius

Radius = \frac{25}{2}

Step 6: Calculate the area of the sector (Semi circle)

EXAMPLE: \frac{1}{2} \pi r^2

\frac{1}{2} * 3.14 * (\frac{25}{2})^2

327.38 cm^2 .

Step 7: Find the area of the right angle triangle

EXAMPLE: Area of right angled triangle QPR = \frac{1}{2} * base * height

=\frac{1}{2} × 7 × 24

= 84 cm^2

Step 8: Determine the Area of the shaded segments

NOTE: Area of the segments shaded = Area of sector OQPR - Area of triangle PQR

Area of the segments shaded  = 327.38 - 84

= 243.38 cm^2