Step 1: Note down the given values and examine the given figure

Step  2: Find the unknown area by the known areas.

            NOTE: Area of the segments shaded = Area of sector OQPR - Area of triangle PQR

Step 3: Make sure is it a right angle triangle or not

            NOTE: Since QR is diameter, ∠QPR = 90° (Angle in a semicircle)

Step 4: Calculate the diameter of the circle by using the Pythagoras theorem

            EXAMPLE: Using Pythagoras Theorem In ∆QPR,

                               QR^2 = PQ^2 + PR^2

                                                    =   24^2 + 7^2

                                                    = 576 + 49

                                                    = 625

                                          Diameter  QR = 625 = 25 cm.

Step 5: Calculate the radius of the circle

          NOTE: Diameter = 2 * radius

                       Radius = \frac{25}{2}

Step 6: Calculate the area of the sector (Semi circle)

            EXAMPLE: \frac{1}{2} \pi r^2

                               \frac{1}{2} * 3.14 * (\frac{25}{2})^2

                               327.38 cm^2 .

Step 7: Find the area of the right angle triangle

            EXAMPLE: Area of right angled triangle QPR = \frac{1}{2} * base * height   

                                         =\frac{1}{2} × 7 × 24

                                                     = 84 cm^2

Step 8: Determine the Area of the shaded segments

            NOTE: Area of the segments shaded = Area of sector OQPR - Area of triangle PQR

                      Area of the segments shaded  = 327.38 - 84

                                                                        = 243.38 cm^2