Find the area of the segments shaded in figure, if PQ = 24 cm., PR = 7 cm. and QR is the diameter of the circle with centre O (Take π = \frac{22}{7} )

Step 1: Note down the given values and examine the given figure
Step 2: Find the unknown area by the known areas.
NOTE: Area of the segments shaded = Area of sector OQPR - Area of triangle PQR
Step 3: Make sure is it a right angle triangle or not
NOTE: Since QR is diameter, ∠QPR = 90° (Angle in a semicircle)
Step 4: Calculate the diameter of the circle by using the Pythagoras theorem
EXAMPLE: Using Pythagoras Theorem In ∆QPR,
QR^2 = PQ^2 + PR^2
= 24^2 + 7^2
= 576 + 49
= 625
Diameter QR = 625 = 25 cm.
Step 5: Calculate the radius of the circle
NOTE: Diameter = 2 * radius
Radius = \frac{25}{2}
Step 6: Calculate the area of the sector (Semi circle)
EXAMPLE: \frac{1}{2} \pi r^2
\frac{1}{2} * 3.14 * (\frac{25}{2})^2
327.38 cm^2 .
Step 7: Find the area of the right angle triangle
EXAMPLE: Area of right angled triangle QPR = \frac{1}{2} * base * height
=\frac{1}{2} × 7 × 24
= 84 cm^2
Step 8: Determine the Area of the shaded segments
NOTE: Area of the segments shaded = Area of sector OQPR - Area of triangle PQR
Area of the segments shaded = 327.38 - 84
= 243.38 cm^2