#### Find the equation of the line with the slope -2/3 passing through the point (-5,3).

y=mx+b

I need help with this question I dont know how to start and finish this.

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y=mx+b

I need help with this question I dont know how to start and finish this.

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I found an answer from www.quora.com

How to **find** the **y**-intercept of a **line** if I have the **slope** - Quora

Solve **for b** example: **y** =**mx**+**b** suppose youre **slope** is **5**. ... How do I **find** the
**slope** of a **line passing through** 2 **points** in standard form and **slope** intercept form
?

For more information, see How to **find** the **y**-intercept of a **line** if I have the **slope** - Quora

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I found an answer from stackoverflow.com

Perpendicular on a **line** from a given **point** - Stack Overflow

Nov 28, 2009 **...** In algebra, **for** any linear **equation y**=**mx** + **b**, the perpendiculars will all have a ...
To **find** the perpendicular of a given **line** which also **passes through** a particular
**point** (x, **y**), solve the **equation y** = **(-**1/m)x + **b**, ... You **know** both the **point** and the
**slope**, so the **equation for** the new **line** is: ... I hope this **helps**.

For more information, see Perpendicular on a **line** from a given **point** - Stack Overflow

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I found an answer from matheducators.stackexchange.com

secondary education - Should I be teaching **point**-**slope formula** to ...

Nov 2, 2015 **...** We just **start** using it (because it's the right way to talk about tangent ... answered
Nov **3** '15 at 21:12 .... **point**-**slope** form down cold they can probably **pass** the
whole class. ... of a **line**, and I **don't want** to **see slope**-intercept **for** the first five
weeks. ... **by** the **end** of five weeks they can go back... but most **don't** :).

For more information, see secondary education - Should I be teaching **point**-**slope formula** to ...

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calculus - How can I **find** the coordinates of a **point** given a function ...

Let the required **point** on the curve be ( k , k 2 − **3** ) . Then the **slope** of the tangent
at that **point** equals 2 k . Further we **know** it **passes through** two **points** ( − 2 , 0 ) ...

For more information, see calculus - How can I **find** the coordinates of a **point** given a function ...

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How to **find** the **equation** of a tangent/normal **line** of a curve at a ...

To **find** the **equations** of the tangent and the normal (perpendicular) **lines** at a
given **point** on a curve, you **need** to **know** two things: 1. ... a **point** (x, **y**) that each
**line passes through**. ... Graphically, the derivative f ′(x) is the **slope** of a curve at
any **point** (x, **y**) on the curve, as well as the **slope** of the ..... Related **Questions**.

For more information, see How to **find** the **equation** of a tangent/normal **line** of a curve at a ...

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I found an answer from www.reddit.com

How do i solve this : learnmath

A linear function goes **through** the **point** f (**5**) = 1 and parallel to g (x) = 3x + **3**,
**determine** f (-1) ... **Questions**, **no** matter how basic, will be answered (to the best
ability of ... To receive the best **help**, **please** use the following format: ... **y**= **mx**+**b**,
we can **find** that m=**3**, and therefore the **slope** of f(x) must also be **3**.

For more information, see How do i solve this : learnmath

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**Equation** of **line** Parallel to **Line** of **Equation** 3x+2y-**5**=0 And **Passes** ...

Studying **for** a Math test, I **don't know** if the answer I got is right. ... To **begin** with,
we can rewrite the given **line equation** as 3x + 2y = **5**. ... Finally, plug in the **point** (
**3**, -**5**), that is set x = **3** and **y** = -**5**, and then solve **for b**. ... Now, let's **start** with an
**equation** in just **y** = **mx** and would be obviously parallel. **y** = **(-3**/2)x.

For more information, see **Equation** of **line** Parallel to **Line** of **Equation** 3x+2y-**5**=0 And **Passes** ...

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I found an answer from stackoverflow.com

draw the altitude of a triangle - Stack Overflow

Right, after you have your yIntercept and the **slope** of the perpendicular **line**, you
**need** to construct a system of 2 linear **equations** with 2 unknowns (x0, y0) from
the 2 **line equations** (bc **line** and **line passing through** a). The solution to ... Let a
**point** p along bc , given by the vector **equation** p = **b** + t bc , where t is a
parameter.

For more information, see draw the altitude of a triangle - Stack Overflow

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geometry - **Find equation** of the straight **line** satisfying some ...

**For** part **b**, a **line** parallel to x-axis has a **slope** of 0 .... two **points** that are on the
**line**. Therefore if you **know** the **slope** of a **line** and another **point** that lies on it, say.

For more information, see geometry - **Find equation** of the straight **line** satisfying some ...

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I found an answer from en.wikipedia.org

Linear **equation** - Wikipedia

**3** More than two variables; 4 **See** also; **5** Notes; 6 References; 7 External links.
One variable[edit]. Frequently the term linear **equation** refers implicitly to the case
of just one ... For the case of several simultaneous linear equations, see System
of linear ..... The **slope** of a straight **line**, usually introduced as rise **over** run, is the
...

For more information, see Linear **equation** - Wikipedia

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I found an answer from en.wikipedia.org

**Line** (geometry) - Wikipedia

The notion of **line** or straight **line** was introduced **by** ancient mathematicians to
represent .... In two dimensions, i.e., the Euclidean plane, two **lines** which **do not**
intersect ... These forms (**see** Linear **equation for** other forms) are generally
named **by** ... (x0, **y**0, z0) is any **point** on the **line**. a, **b**, and c are related to the
**slope** of the ...

For more information, see **Line** (geometry) - Wikipedia

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I found an answer from answers.yahoo.com

Write an **equation** in **slope** intercept form.? | Yahoo Answers

**Help** ... **y**=**mx** + **b**. "m" is the **slope** of the **line** (it's the coefficient of the x term, along
... We shall **see** that way in your second **question**. ... Asker's rating **5** out of **5** ...
First, you have to **find** the **equation for** the **line** that **passes through** (**3**,**3**) and (0,6).
... This means that the **slope** of the **line passing through** the **point (-3**, -1) is m = -1.

For more information, see Write an **equation** in **slope** intercept form.? | Yahoo Answers

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Calculus optimization **problem**? | Yahoo Answers

The **equation** of the **line** would be **y** = m(x-6) + 10 or **y** = **mx** - 6m + 10. ... school
methods to **find** the **equation** of the **line** with **slope** m = = -**5**/**3** and **through** (6, 10).

For more information, see Calculus optimization **problem**? | Yahoo Answers