Krishna
0

Step 1: Take the given inverse trigonometric function

\tan^{-1} (\sqrt{3})

NOTE: \tan^{-1} \theta is defined as a function with values restricted to the range $[0, \frac{\pi}{2}$)

Step 2: Determine the required angle of the function

Let \tan^{-1} (\sqrt{3}) = \theta

\tan \theta = \sqrt{3}

\tan \theta = \tan 60\degree

\theta = 60\degree                                  ( \because   A basic reference triangle looks like: