Krishna
0

Step 1: Take the given inverse trigonometric function

                 \tan^{-1} (\sqrt{3})

                NOTE: \tan^{-1} \theta is defined as a function with values restricted to the range [math][0, \frac{\pi}{2}[/math])

              

Step 2: Determine the required angle of the function

              Let \tan^{-1} (\sqrt{3}) = \theta

                     \tan \theta = \sqrt{3}

                     \tan \theta = \tan 60\degree

                     \theta = 60\degree                                  ( \because   A basic reference triangle looks like:

                                                                                        enter image source here 

                                                                                 \tan \theta = \frac{opposite}{adjacent}

                                                                                  \tan 60\degree = \frac{\sqrt{3}}{1}