Mahesh Godavarti
0

Okay, the distribution is 1) no doublets, 2) 1 doublet, 3) 2 doublets, and 4) 3 doublets.


Probability of no doublets = \frac{5}{6}^3

Probability of 1 doublet = 3 \frac{1}{6} \frac{5}{6}^2

Probability of 2 doublets = 3 \frac{1}{6}^2 \frac{5}{6}

Probability of 3 double = \frac{1}{6}^3