Find the probability of getting a head when a coin is tossed once. Also, find the probability of getting a tail.

Anonymous
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Step 1: Find the total number of possible out comes.
NOTE: In the experiment of tossing a coin once, the number of possible
outcomes is two - Head (H) and Tail (T).
Step 2: Find the number of out comes favorable.
Let E be the event 'getting a head'.
The number of outcomes favourable to E, (i.e., of getting a head) is 1.
Step 3: Calculate the probability
Therefore, P(E) = P (head) =\frac{\text{Number of outcomes favourable to E}}{\text{Number of all possible outcomes}}
P(E) = \frac{1}{2}
Similarly, if F is the event 'getting a tail',
then, P(F) = P(tail) = \frac{1}{2}