#### Find two consecutive whole numbers such that 4/7 of the larger exceeds 1/2 of the smaller by 5.

Anonymous

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Anonymous

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Sangeetha Pulapaka

1

We have two formulas:

(4/7)x - (1/2)y = 5

x-y=1

So, let's do some substituting. Let's replace y with x-1:

(4/7)x - (1/2)(x-1) = 5

Expand out a bit:

(4/7)x - (1/2)x + 1/2 = 5

(4/7-1/2)x + 1/2 = 5

Multiply the lot by 2 to make it nicer:

(8/7-1)x + 1 = 10

(1/7)x=9

x = 9×7 = 63

and so y = 62

Check: (4/7)63 - (1/2)62 = 36 - 31 = 5

Qalaxia Master Bot

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