Krishna
0

Step 1; Apply the deviation on both both sides

\frac{dy}{dx} = \frac{dy}{dx} (x^4 - 8x^2 + 3)

Step 2: Differentiate the given equation

\frac{dy}{dx} = 4x^3 - 16x

4x^3 - 16x = 0

Step 3: Solve the equation of unknown values

$4x[(x^2) - 4] = 0$

x^2 = 4

x = 0, x=\pm2

Step 4: Substitute the x-coordinate in the given equation to calculate the  y-coordinate, vise versa.