Krishna
0

Step 1:  Read the question and find the sample space

              Event:  Tossing two different coins (Rs. 1 and Rs 2)

                          So sample space = {HH, HT, TT, TH}

                                                      = 4

              


Step 2:  Calculate the number of outcomes favourable to the event

                Favourable outcomes to get at least one head = {(H,H) , (H,T), (T,H)}

                  So, the number of outcomes favourable = 3.


                Hence, the probability that she gets at least one head = \frac{The\ number\ of\ outcomes\ favourable}{Total\ number\ of\ outcomes}

                                                                                                       = \frac{3}{4}