The lock has 5 digits, and there are 10 digits to choose from. The number of ways the codes can be formed with all digits being different is in ^{10}P_{5} ways.

Using the permutation formula which is ^{n}P_{r} = \frac{n!}{(n-r)!}

^{10}P_{5} = \frac{10!}{(10-5)!} = \frac{10!}{5!} = 7 \cdot 8 \cdot 9 \cdot 10= 30,240 ways.

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How **many** $4$-**digit lock** combinations are possible **if each digit** in ...

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A **lock** contains **5 digits** in its **code**. How **many codes can** be **formed** ...

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Cracking Your PIN **Code**: Easy as 1-2-3-4

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What do **digits** in phone **numbers** mean? | HowStuffWorks

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the area **code is** the city, the prefix **is** the street and the line number **is** the **house**.

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