If the perimeter of the isosceles right triangle is (6 + 3\sqrt{2}), then the area of the triangle is___

Step 1: Know about the isosceles right triangle
NOTE: Triangle is isosceles right triangle, the length of two sides will be
equal. And Pythagoras Law is applicable.
Step 2: Assume any variables as lengths of the isosceles right triangle.
NOTE: Let "x" be the length of one equal side, and "y" be the length of
hypotenuse side
Step 3: Set up an equation using the variables and given perimeter measurement.
EXAMPLE: perimeter of triangle = 6 + 3 \sqrt{2}
x + x + y = 6 + 3 \sqrt{2}
2x + y = 6 + 3 \sqrt{2} -----------------(1)
Step 4: Find the "y" value by using the Pythagoras Law.
EXAMPLE: y^2 = x^2 + x^2
y^2 = 2x^2
y = \sqrt{2}x
Step 5: Substitute y value in the equation (1) (see step 3). To find the length.
EXAMPLE: 2x + y = 6 + 3 \sqrt{2}
2x + \sqrt{2}x = 6 + 3 \sqrt{2}
x = 3
Step 6: Plug the base and height into your area formula.
x length of the equal side = 3
\frac{1}{2}b*h = \frac{1}{2} (3*3)
= 4.5 square meter