I found an answer from www.slac.stanford.edu

LCLS-II

Apr 8, 2011 **...** The Linac Coherent **Light** Source II (LCLS-II) Project will construct the ...
arrangement of **two** undulators separated **by** a monochromator, and ... pulses to
one of four **experiment** stations in operation today[**2**]. **By** ... **by** one **wavelength** λ
relative to the electron bunch per undulator ... 780 **nm wavelength** range.

For more information, see LCLS-II

I found an answer from www.quora.com

In a **double**-**slit experiment using** the **light** of **wavelength 600 nm**, the ...

In a **double**-**slit experiment using** the **light** of **wavelength 600 nm**, the **angular**
**width** of a **fringe formed** on a **distant screen** is 0.1 degree . What is the **spacing**
**between** the **two slits**? 2 Answers. Ganga Kartha, lives in Newark, NJ. Updated 3
...

For more information, see In a **double**-**slit experiment using** the **light** of **wavelength 600 nm**, the ...

I found an answer from www.khanacademy.org

**Young's double slit** introduction (video) | Khan Academy

We can see interference in action if we shine laser **light** through two **slits** onto a
screen. ... Aren't the bright **fringes** supposed to be of same intensity in **Young's**
**double slit experiment** ? ... spunky sam blue style avatar for user
**PhysicsEnthusiast** ... their **waves** can be specified to 1nm. central **fringe** will be
double the **width** of ...

For more information, see **Young's double slit** introduction (video) | Khan Academy

Given that

Wavelength of the light \lambda = 600 nm = 600 * 10^{-9} m

Angular width of the fringe \theta = 0.1\degree

Spacing between the two slits = ?

Step 1: Step up a formula for distance between the two slits.

We know that

The angular fringe width depends on the light wavelength used, and the distance between two slits

\theta = \frac{\lambda}{d}

Distance between two slits d = \frac{\lambda}{\theta}

Step 2: Identifying the spacing between the two slits

d = \frac{600 * 10^{-9}}{0.1* \frac{\pi}{180}} \because1\degree=\frac{\pi}{180}rad

d = \frac{600 * 180 * 10^{-9}}{0.1 \pi }

d = 3.44 *10^{-4} m

d = 0.344 mm

Therefore, spacing between the two slits d = 0.344 mm