I found an answer from www.slac.stanford.edu

LCLS-II

Apr 8, 2011 ... The Linac Coherent Light Source II (LCLS-II) Project will construct the ... arrangement of two undulators separated by a monochromator, and ... pulses to one of four experiment stations in operation today[2]. By ... by one wavelength λ relative to the electron bunch per undulator ... 780 nm wavelength range.

For more information, see LCLS-II

I found an answer from www.quora.com

In a double-slit experiment using the light of wavelength 600 nm, the ...

In a double-slit experiment using the light of wavelength 600 nm, the angular width of a fringe formed on a distant screen is 0.1 degree . What is the spacing between the two slits? 2 Answers. Ganga Kartha, lives in Newark, NJ. Updated 3  ...

For more information, see In a double-slit experiment using the light of wavelength 600 nm, the ...

I found an answer from www.khanacademy.org

Young's double slit introduction (video) | Khan Academy

We can see interference in action if we shine laser light through two slits onto a screen. ... Aren't the bright fringes supposed to be of same intensity in Young's double slit experiment ? ... spunky sam blue style avatar for user PhysicsEnthusiast ... their waves can be specified to 1nm. central fringe will be double the width of ...

For more information, see Young's double slit introduction (video) | Khan Academy

Given that

Wavelength of the light \lambda = 600 nm = 600 * 10^{-9} m

Angular width of the fringe \theta = 0.1\degree

Spacing between the two slits = ?

Step 1: Step up a formula for distance between the two slits.

              We know that

            The angular fringe width depends on the light wavelength used, and the distance between two slits      

                   \theta = \frac{\lambda}{d}

                Distance between two slits   d = \frac{\lambda}{\theta}   

Step 2: Identifying the spacing between the two slits              

                       d = \frac{600 * 10^{-9}}{0.1* \frac{\pi}{180}}                \because1\degree=\frac{\pi}{180}rad

                       d = \frac{600 * 180 * 10^{-9}}{0.1 \pi }     

                       d = 3.44 *10^{-4} m

                       d = 0.344 mm

                 Therefore, spacing between the two slits d = 0.344 mm