Let us consider an equation \frac{1}{2} mv^2 = mgh where m is the mass of the body, v its velocity, g is the acceleration due to gravity and h is the height. Check whether this equation is dimensionally correct.

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Why does the formula for kinetic energy have a half in it? - Quora
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According to the Principle of Homogeneity, the dimensions of each term of a dimensional equation on both sides should be the same. This theory allows us to convert the units from one form to another.
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Given that
\frac{1}{2} mv^2 = mgh
Step 1: Set up a dimensional formula for kinetic energy
K.E = \frac{1}{2} mv^2 where, m - mass and v - velocity
Dimensional formula [math] = [M] [L^2 T^{-2}] [/math]
[math]=\ [ML^2T^{-2}][/math] ....................(1)
Step 1: Set up a dimensional formula for potential energy
P.E = mgh , where m - mass, g - acceleration due to gravity ( 9.8 m/s^2 ).
Dimensional formula [math] = [M] [LT^{-2}] [L] [/math]
[math] = [M L^2 T^{-2}] [/math] ...................(2)
From equation (1) and (2)
\frac{1}{2} mv^2 = mgh
[math] [M L^2 T^{-2}] = [M L^2 T^{-2}] [/math]
L.H.S = R.H.S
Since the dimensions of the LHS and RHS are the same, the equation is dimensionally correct.