I found an answer from ntrs.nasa.gov

NASA UNIVERSITY RESEARCH CENTERS

**Effect** of Land-**Use** Practice on Soil Moisture Variability for Soils ... inelastic
scattering process in which **light** from a **laser** at **wavelength** Ll is converted into
**light** at.

For more information, see NASA UNIVERSITY RESEARCH CENTERS

I found an answer from byjus.com

**Einstein's** Explanation Of **Photoelectric Effect** - Threshold Frequency ...

Learn about **Einstein's Theory** of **Photoelectric Effect** at BYJU'S. ... did not pursue
the **matter** as he felt sure that it could be explained by the **wave theory**. ... This
implies that the **kinetic energy** of electrons increases with **light** intensity. ... Thus,
the **energy** of a **photon** with this frequency must be the **work function** of the metal.

For more information, see **Einstein's** Explanation Of **Photoelectric Effect** - Threshold Frequency ...

Given that

Wavelength of light \lambda = 488 nm = 488 * 10^{-9} m

Potential of photoelectrons V = 0.38 V

Work function of material = ?

Step 1: Get an expression for the work function

We know that

By conservation by law, Energy E = eV...........................(1)

Where, e - electric charge and V - potential of electrons

Einstein's photoelectric equation

Energy of proton E=h\upsilon\ -\ \phi

eV = h \frac{c}{\lambda} - \phi \because \text{ frequency } \upsilon = \frac{c}{\lambda}

Work function \phi = h \frac{c}{\lambda} - eV

Step 2: Plug in the know values in the above work function equation

Planck's constant h = 6.626*10^{-34} Js,

Speed of light c = 3*10^{8} m/s

Charge of electron e = 1.6*10^{-19} C

\phi = h \frac{c}{\lambda} - eV

\phi = \frac{6.626 * 10^{-34} * 3*10^{8}}{488 * 10^{-9}} - 1.6*10^{-19} * 0.38

\phi=\frac{\left(6.626*10^{-34}\right)\cdot\left(3\cdot10^8\right)}{\left(488*10^{-9}\right)\cdot\left(1.6\cdot\ 10^{-19}\right)}-\frac{\left(1.6*10^{-19}*0.38\right)}{1.6\cdot10^{-19}}

\phi=\frac{\left(4.0734*10^{-19}\right)}{1.6\cdot10^{-19}}-0.38

\phi = 2.5458 - 0.38

\phi = 2.1658 eV

Hence, work function of the material \phi = 2.1658 eV