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I found an answer from ntrs.nasa.gov

NASA UNIVERSITY RESEARCH CENTERS

Effect of Land-Use Practice on Soil Moisture Variability for Soils ... inelastic scattering process in which light from a laser at wavelength Ll is converted into light at. Qalaxia Master Bot
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I found an answer from byjus.com

Einstein's Explanation Of Photoelectric Effect - Threshold Frequency ...

Learn about Einstein's Theory of Photoelectric Effect at BYJU'S. ... did not pursue the matter as he felt sure that it could be explained by the wave theory. ... This implies that the kinetic energy of electrons increases with light intensity. ... Thus, the energy of a photon with this frequency must be the work function of the metal.

For more information, see Einstein's Explanation Of Photoelectric Effect - Threshold Frequency ... Pravalika
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Given that

Wavelength of light \lambda = 488 nm = 488 * 10^{-9} m

Potential of photoelectrons V = 0.38 V

Work function of material = ?

Step 1: Get an expression for the work function

We know that

By conservation by law, Energy E = eV...........................(1)

Where, e - electric charge and V - potential of electrons

Einstein's photoelectric equation

Energy of proton E=h\upsilon\ -\ \phi

eV = h \frac{c}{\lambda} - \phi                       \because \text{ frequency } \upsilon = \frac{c}{\lambda}

Work function  \phi = h \frac{c}{\lambda} - eV

Step 2: Plug in the know values in the above work function equation

Planck's constant h = 6.626*10^{-34} Js,

Speed of light c = 3*10^{8} m/s

Charge of electron e = 1.6*10^{-19} C

\phi = h \frac{c}{\lambda} - eV

\phi = \frac{6.626 * 10^{-34} * 3*10^{8}}{488 * 10^{-9}} - 1.6*10^{-19} * 0.38

\phi=\frac{\left(6.626*10^{-34}\right)\cdot\left(3\cdot10^8\right)}{\left(488*10^{-9}\right)\cdot\left(1.6\cdot\ 10^{-19}\right)}-\frac{\left(1.6*10^{-19}*0.38\right)}{1.6\cdot10^{-19}}

\phi=\frac{\left(4.0734*10^{-19}\right)}{1.6\cdot10^{-19}}-0.38﻿

\phi = 2.5458 - 0.38

\phi = 2.1658 eV

Hence,  work function of the material   \phi = 2.1658 eV