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Effect of Land-Use Practice on Soil Moisture Variability for Soils ... inelastic scattering process in which light from a laser at wavelength Ll is converted into light at.

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Einstein's Explanation Of Photoelectric Effect - Threshold Frequency ...

Learn about Einstein's Theory of Photoelectric Effect at BYJU'S. ... did not pursue the matter as he felt sure that it could be explained by the wave theory. ... This implies that the kinetic energy of electrons increases with light intensity. ... Thus, the energy of a photon with this frequency must be the work function of the metal.

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Given that

Wavelength of light \lambda = 488 nm = 488 * 10^{-9} m

Potential of photoelectrons V = 0.38 V  

Work function of material = ?

Step 1: Get an expression for the work function

               We know that

                  By conservation by law, Energy E = eV...........................(1)

                       Where, e - electric charge and V - potential of electrons  

                  Einstein's photoelectric equation

                        Energy of proton E=h\upsilon\ -\ \phi

                                                 eV = h \frac{c}{\lambda} - \phi                       \because \text{ frequency } \upsilon = \frac{c}{\lambda}   

                       Work function  \phi = h \frac{c}{\lambda} - eV     

Step 2: Plug in the know values in the above work function equation

                     Planck's constant h = 6.626*10^{-34} Js,

                    Speed of light c = 3*10^{8} m/s   

                    Charge of electron e = 1.6*10^{-19} C

                                             \phi = h \frac{c}{\lambda} - eV

                                             \phi = \frac{6.626 * 10^{-34} * 3*10^{8}}{488 * 10^{-9}} - 1.6*10^{-19} * 0.38                                             

                                            \phi=\frac{\left(6.626*10^{-34}\right)\cdot\left(3\cdot10^8\right)}{\left(488*10^{-9}\right)\cdot\left(1.6\cdot\ 10^{-19}\right)}-\frac{\left(1.6*10^{-19}*0.38\right)}{1.6\cdot10^{-19}}                                            

                                            \phi=\frac{\left(4.0734*10^{-19}\right)}{1.6\cdot10^{-19}}-0.38

                                             \phi = 2.5458 - 0.38

                                             \phi = 2.1658 eV

                Hence,  work function of the material   \phi = 2.1658 eV