Probability of not spinning a 7 = 1 - 1/10 = 9/10

Probability of tossing heads = 1/2

Probability of spinning a 3 = 1/10

So, the compound probability = 9/10 x 1/2 x 1/10 = 9/200.

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What are the odds of getting **heads 7** times in a row in 40 tries of ...

Let's count the number of ways **not** to get **7 heads** in a row. ... in the second factor,
the x (T) was chosen, **then** x**3** (HHT), **then** x (T), **then** x2 (HT), to get ... To count
the number of sequences of 40 **flips** that do **not** contain **7** consecutive **heads**, we
...

For more information, see What are the odds of getting **heads 7** times in a row in 40 tries of ...

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HW1 Solutions

Oct 5, 2016 **...** **3**. (2 pts.) Let A be the event that the first **flip** is a **Heads**. List all the outcomes ...
For |D|, note that a outcome is **not** in D if the first and **third flips** are ... Comment:
Note that if we place both coins on **7**, **then** we need both rolls of.

For more information, see HW1 Solutions

I found an answer from www.khanacademy.org

Compound **probability** of **independent events** (video) | Khan Academy

You'll become familiar with the concept of **independent events**, or that one event
... But isn't it also true that the **probability** of six **coins flips** resulting in at least one
T is very high? ... For instance if you roll a **dice** you can't get both three and four.

For more information, see Compound **probability** of **independent events** (video) | Khan Academy