One card is drawn from a well-shuffled deck of 52 cards. Calculate the probability that the card will (i) be an ace, (ii) not be an ace.

Step 1: Understand the given question and find the number of possible outcomes.
The number of possible outcomes = 52 (GIVEN)
Step 2: Calculate the number of fevourable out comes.
There are 4 aces in a deck.
(i) Let E be the event 'the card is an ace.
The number of outcomes favourable to E = 4
(ii) Let F be the event 'card drawn is not an ace.
The number of outcomes favourable to the event F = 52 - 4 = 48
Step 3: Find the probability that the card will be an ace and not be an ace.
Probability P(E)=\frac{number\ of\ fevourable\ out\ comes}{total\ number\ of\ possible\ out\ comes}
Probability of that the card will be an ace P(E) = \frac{4}{52} = \frac{1}{13}
Probability of that the card will not be an ace P(F) = \frac{48}{52} =\frac{12}{13}
or
We known that complementary events, Here F is the same as 'not E' because there are only two events.
P(F) + P(B) or (P (\bar{F})) = 1
P(F) = 1 - P(B)
P(F) = 1 - \frac{1}{13}= \frac{12}{13}