Prove that a line joining the midpoints of any two sides of a triangle is parallel to the third side. (Using converse of basic proportionality theorem)

Step 1:According to the given data construct a imaginary figure
Given:
ΔABC in which D and E are the mid points of AB and AC respectively
such that AD = BD and AE = EC.
To Prove: DE || BC
Step 2: Use the given hints in the question to prove the required equation
EXAMPLE: AD = BD
\frac{AD}{BD} = 1.............................(1)
AE = EC
\frac{AE}{EC} = 1..............................(2)
Step 3: Compare the equation (1) and (2)
\frac{AD}{DB} = 1, \frac{AE}{EC} = 1.
From this we can write \frac{AD}{DB} = \frac{AE}{EC}
Step 4: Apply the converse of basic proportional theorem
THEOREM: If a line divides any two sides of a triangle in the same ratio
then the line must parallel to the third side.
EXAMPLE: In ∆ABC,
∴ DE || BC
Hence , the line joining the mid points of any two sides of a triangle is parallel to the third side....