Step 1: Take down the given equation  

            GIVEN: \sqrt{\frac{1 + \cos \theta}{1 - \cos \theta}} = \cosec \theta + \cot \theta

Step 2:  Take the L.H.S of the equation and think about the possible ways to prove R.H.S

                NOTE:   \sqrt{\frac{1 + \cos \theta}{1 - \cos \theta}}

Step 3: Rationalize the irrational denominator

            EXPLANATION; You can't solve an equation that contains a fraction with an irrational denominator, which means that the denominator contains a term with a radical sign. This includes square, cube and higher roots. Getting rid of the radical sign is called rationalizing the denominator. 

                EXAMPLE: \sqrt{\frac{1 + \cos \theta}{1 - \cos \theta}}

                                    Divide and multiply by 1+\cos\theta  

                                  =   \sqrt{\frac{1 + \cos \theta}{1 - \cos \theta} \frac{1 + cos \theta}{1 + cos \theta}}

                                  =     \sqrt{\frac{(1 + \cos \theta)^2}{(1 - \cos \theta)(1 + cos \theta)}}

                                  =     \sqrt{\frac{(1 + \cos \theta)^2}{1^2 - \cos^2 \theta}}

                                =     \frac{1 + \cos \theta}{\sin \theta}  (Since, \sin^2 \theta = 1 - \cos^2 \theta )

Step 3: Separate the denominator and simplify for R.H.S

              EXAMPLE:   \frac{1}{\sin \theta} + \frac{ \cos \theta}{sin \theta}

                               \cosec \theta + \cot \theta       

                                                              (since, \cosec \theta = \frac{1}{\sin \theta}

                                                                                   \cot \theta = \frac{\cos \theta}{\sin \theta}   )

                          Hence, proved