Show that x^2 + 6x + 11 can be written as (x + p)^2 + q where p and q are integers to be found.

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Step 1: Note-down the given quadratic equation and compare it with the standard form ax^2 + bx + c
EXAMPLE: 2x^2 - 3x - (k+1)
ax^2 + bx + c
Where a = 2, b = - 3 and c = - (k+1)
Step 2: Calculate the B and C values
NOTE: ax^2 + bx + c write in the form of the (Ax+B)^2+C\ \ \ \ .
Comparing this two equations shows that
b = 2B or B = \frac{b}{2} and c = B^2 + C or C = c - B^2 since A = 1
EXAMPLE: x^2 - 6x + 13
B = \frac{-6}{2} and C = 13 - (-3)^2
B = -3 and C = 4
Step 3: Substitute these values in the equation (x + B)2 + C.
EXAMPLE: (x - 3)^2 + 4
Step 4: Compare the two equations and note down the unknown values
EXAMPLE: (x - 3)^2 + 4 = (x+p)^2+q