#### Show that triangles ABC and A'BC', in the figure below, are similar.

Anonymous

0

Krishna

0

Step 1: Look at the given figure and note down the given measurements

NOTE: AA' = 6, A'B = 4, CC' = 3, and C'B = 2

Step 2: Calculate the ratios of the lengths of the corresponding sides.

\frac{BA}{BA'} = \frac{AA' + A'B}{A'B} = \frac{10}{4}

\frac{BC}{BC'}=\frac{CC'+BC'}{C'B}=\frac{5}{2}

Step 3: Conclude that the given triangle are similar if the two triangles have two sides whose lengths are proportional and a congruent angle included between the two sides.

\frac{BA}{BA'} = \frac{10}{4} = \frac{5}{2}

\frac{BC}{BC'}=\frac{5}{2}

So, The two triangles are similar.