Show that triangles ABC and A'BC', in the figure below, are similar.

Anonymous
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Step 1: Look at the given figure and note down the given measurements
NOTE: AA' = 6, A'B = 4, CC' = 3, and C'B = 2
Step 2: Calculate the ratios of the lengths of the corresponding sides.
\frac{BA}{BA'} = \frac{AA' + A'B}{A'B} = \frac{10}{4}
\frac{BC}{BC'}=\frac{CC'+BC'}{C'B}=\frac{5}{2}
Step 3: Conclude that the given triangle are similar if the two triangles have two sides whose lengths are proportional and a congruent angle included between the two sides.
\frac{BA}{BA'} = \frac{10}{4} = \frac{5}{2}
\frac{BC}{BC'}=\frac{5}{2}
So, The two triangles are similar.