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**Suppose**, **we think** of **fission** of a ^**5626Fe nucleus into** two equal ...

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Nuclear reaction equation of ^{56}_{26} Fe

^{56}_{26} Fe \rightarrow ^{28}_{13} AI + ^{28}_{13} AI

Q-value of a nuclear reaction [math]=[\text{ mass of }_{26}^{56}Fe-2\cdot\ \text{mass of }(_{13}^{28}AI)]c^2[/math]

Given that

m(^{56}_{26} Fe) = 55.93494 u

m(^{28}_{13} AI) = 27.98191 u

\text{ Q -value } = 55.93494 - 2 * (27.98191) c^2 u

\text{ Q -value } = - 0.02888 c^2 u

\text{ Q -value } = - 0.02888 c^2 * 931.5 MeV/c^2 \because 1 u = 931.4 MeV/c^2

\text{ Q -value } = - 26.902 MeV

Fission has a negative Q-value. As a result, energetically, fission is not feasible. The Q-value must be positive in order for a fission reaction to be energetically feasible.