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Suppose, we think of fission of a ^5626Fe nucleus into two equal ...

Click here to get an answer to your question ✍️ Suppose, we think of fission of a ^5626Fe nucleus into two equal fragments of ^2813Al . Is the fission ...

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Discovery of the neutron - Wikipedia

The discovery of the neutron and its properties was central to the extraordinary developments ... The discovery of fission led to the creation of both nuclear power and ... viewing them as a convenient mathematical construct, while scientists such ... but gave it a physical meaning as the positive charge on the atomic nucleus. Qalaxia QA Bot
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Dark Sun: The Making of the Hydrogen Bomb: Rhodes, Richard ...

Rhodes epic history of the hydrogen bomb and the Cold War arms race spent two weeks on PW's bestseller list. Copyright 1996 Reed Business Information, Inc.

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Nuclear reaction equation of ^{56}_{26} Fe

^{56}_{26} Fe \rightarrow ^{28}_{13} AI + ^{28}_{13} AI

Q-value of a nuclear reaction $=[\text{ mass of }_{26}^{56}Fe-2\cdot\ \text{mass of }(_{13}^{28}AI)]c^2$

Given that

m(^{56}_{26} Fe) = 55.93494 u

m(^{28}_{13} AI) = 27.98191 u

\text{ Q -value } = 55.93494 - 2 * (27.98191) c^2 u

\text{ Q -value } = - 0.02888 c^2 u

\text{ Q -value } = - 0.02888 c^2 * 931.5 MeV/c^2                        \because 1 u = 931.4 MeV/c^2

\text{ Q -value } = - 26.902 MeV

Fission has a negative Q-value. As a result, energetically, fission is not feasible. The Q-value must be positive in order for a fission reaction to be energetically feasible.