The distribution below shows the number of wickets taken by bowlers in one-day cricket matches. Find the mean number of wickets by choosing a suitable method. What does the mean signify?

Step 1: Recall the step-deviation method
The step-deviation method are just simplified form of
the direct method.
Let x_1, x_2, x_3............, x_n be observations with respective
frequencies f_1, f_2,............f_n
Mean = a+\frac{\Sigma f_iu_i}{\Sigma f_i}*h
Where, u_i = \frac{d_i}{h}
d_i = x_i - a
a - Assumed mean
h - is the class size.
Step 2: Choose one among the observations as the assumed mean, and Find the deviation of ‘a’ from each of the observations
NOTE: It is taken somewhere in the middle of all the values of observations
Assumed mean a = 200
Deviation d = x_i - a
x_1=\ 40, a = 200
d = 40 - 200 = - 160
Calculate the deviation for every observation (See the table)
Step 3: Divide the deviation by the class size (h) to calculate u_i
u_i = \frac{d_i}{h}
Class size (h): Generally size of the class is taken as h but it need not be
size of the class always.
Here, the class size varies, and the x_i's are large.
Let us still apply the step deviation method with a = 200 and h = 20.
Then, we obtain the data as given in the table.
Step 4: Calculate the mean using the step deviation formula
Step deviation mean = a + \frac{\Sigma f_iu_i}{\Sigma f_i}*h
= 200 + \frac{-106}{45}*20
Mean = 200 - 47.11
Hence, Mean = 152.89