Your question makes little sense, so as far I can help, we find out the equation of the line which runs through the points (0,3) and (4,6) and convert this into function notation form.

The equation of the line is y = mx+ c where m is the slope and c is the y-intercept.

We use the slope formula between the two points (0,3) (4,6) to find out the slope of the line, m,

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{6-3}{4-0} = \frac{3}{4}

Plug in one of the points in the equation to find the y-intercept.

Plug in (0,3) and m = \frac{3}{4} in y = mx+ c.

to get 3 = \frac{3}{4} \cdot 0 + c

\Rightarrow c = 3

So, the equation of the line is y = \frac{3}{4} x + 3

This is the slope-intercept form. Now let us write this in function notation.

We can write y as a function of x,

f(x) = \frac{3}{4}x + 3

CHECK:

When x = 4, f(4) = \frac{3}{4} \cdot 4 + 3 = 6

So, when x = 4, y = 6, which are one of the points given.

I found an answer from matheducators.stackexchange.com

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I found an answer from en.wikipedia.org

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For more information, see **Function** (mathematics) - Wikipedia