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The **length**, **breadth**, and **thickness** of a **rectangular sheet** of **metal** ...

What is the total **surface area** to **correct significant figures**? ... and **thickness** of a
**rectangular sheet** of **metal** are **4.234 m**, **1.005 m** and **2.01 cm respectively**.

For more information, see The **length**, **breadth**, and **thickness** of a **rectangular sheet** of **metal** ...

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Volume of the rectangular prism = lbh

Surface area of the rectangular prism [math] = 2[lb + bh + hl] [/math] where, l -length, b- breadth and h- height

Rules for Significant Figures

https://byjus.com/chemistry/significant-figures/

Given that

Length of the rectangular sheet = 4.234 m

Breadth of the rectangular sheet = 1.005 m

Thickness rectangular sheet = 2.01 cm = 0.0201 m

Step 1: Calculating the rectangular sheet surface area and the corresponding significant figures.

Length l = 4.234 m, Significant figure = 4

Breadth b = 1.005 m, Significant figure = 4

Thickness(height) h = 0.0201 m, Significant figure = 4

Surface area of the rectangular sheet [math] = 2[lb + bh + hl] [/math]

= 2 (4.234*1.005 + 1.005*0.0201 + 0.0201*4.234)

= 2 (4.25517 + 0.02620 + 0.08510)

= 2*4.360

= 8.7209

= 8.72 m^2 ,

Significant figures = 3

Step 2: Finding the volume of the triangular sheet

Volume of the triangular sheet V = lbh

V = 4.234*1.005*0.0201

V = 0.0855

Hence, volume of the triangular sheet = 0.0855 m^3

Significant figures = 3