#### The line l_1 has equation 3x + 5y – 2 = 0. The line l_2 is perpendicular to l_1 and passes through the point (3, 1).

Find the equation of l_2 in the form y = mx + c, where m and c are constants

Anonymous

0

Find the equation of l_2 in the form y = mx + c, where m and c are constants

Krishna

0

Step 1: Calculate the slope of the given line equation

NOTE: Putting the equation in the form y = mx (+c) and attempting to extract

the m

Step 2: Find the slope of the another line

NOTE: i) Parallel lines have the same slope.

ii) Perpendicular lines have slopes that are opposite reciprocals, like

\frac{a}{b} \text{ and } \frac{-b}{a} The slopes also have

a product of -1.

Step 3: Use the slope of line and a point on line to find its *y*-intercept.

EXAMPLE: Plug the slope m = -2 and the point (-6, 4) into the

slope- intercept formula. Then solve for the *y*-intercept b.

*y* = m*x* + b

4 = -2(-6) + b

Step 4: Use the slope of line and the *y*-intercept of line to find the equation of the line.

EXAMPLE: Plug the slope m = -2 and the *y*-intercept b = -8 into the

slope- intercept formula.

* y* = m*x* + b

* y* = -2*x* + -8