The line l_1 has equation 3x + 5y – 2 = 0. The line l_2 is perpendicular to l_1 and passes through the point (3, 1).

Find the equation of l_2 in the form y = mx + c, where m and c are constants
Find the equation of l_2 in the form y = mx + c, where m and c are constants
Step 1: Calculate the slope of the given line equation
NOTE: Putting the equation in the form y = mx (+c) and attempting to extract
the m
Step 2: Find the slope of the another line
NOTE: i) Parallel lines have the same slope.
ii) Perpendicular lines have slopes that are opposite reciprocals, like
\frac{a}{b} \text{ and } \frac{-b}{a} The slopes also have
a product of -1.
Step 3: Use the slope of line and a point on line to find its y-intercept.
EXAMPLE: Plug the slope m = -2 and the point (-6, 4) into the
slope- intercept formula. Then solve for the y-intercept b.
y = mx + b
4 = -2(-6) + b
Step 4: Use the slope of line and the y-intercept of line to find the equation of the line.
EXAMPLE: Plug the slope m = -2 and the y-intercept b = -8 into the
slope- intercept formula.
y = mx + b
y = -2x + -8