#### The line l_1 has equation y = 3x + 2 and the line l_2 has equation 3x + 2 y – 8 = 0.

The lines l_1 \text{ and } l_2 cross the line y= 1 at the points A and B respectively.

(i) Find the area of triangle ABP.

Anonymous

0

The lines l_1 \text{ and } l_2 cross the line y= 1 at the points A and B respectively.

(i) Find the area of triangle ABP.

Krishna

0

Step 1: Construct a table of values for given line equations

NOTE: Select some values of x and then evaluate those values in the given

equation to get the corresponding values of y.

EXAMPLE: 2x + 3y = 12

x = 0 3 6....

y = 4 2 0.....

Do this for remaining equation for x and y coordinates

Step 2: Plot those points in the xy-axis, and connect them with a straight edge.

NOTE: x = 0 means y- axis and y =0 means x-axis

EXAMPLE: URL: https://www.nextgurukul.in/media/images/q2aanswers/332/kk1_1383639732465.JPG

Step 3: From the figure, notice the base and altitude of the triangle

EXAMPLE: From the figure, notice that the base of the triangle = 5 units

Altitude = 2 units

Step 4: Substitute in the area formula of the triangle

NOTE: \frac{1}{2} base * height

EXAMPLE: \frac{1}{2} (5 *2

Area = 5