The lines l_1 as an equation y = 3x − 6. and l_2 as an equation y = \frac{-1}{3}x +4 cross the x-axis at the points A and B respectively and intersect at the point C (3, 3). (a) Calculate the exact area of triangle ABC.

Step 1: Find the coordinate (x or y) at the point of intersection:
NOTE: If the line intersecting the y-axis then put x = 0 in the equation
If the line intersecting the x-axis then put y = 0 in the equation.
Step 3: Calculate the area of the triangle.
Method 1:
Step 1: Locate the coordinates of the endpoints.
EXAMPLE: The given points M (2, 3) and N (-1, 0), (2, -4.)
Therefore, (x_1, y_1) = (2, 3),(x_2, y_2) = (-1, 0) and (x_3, y_3) = (2, -4).
Step 2: Plug the corresponding coordinates into the Area of triangle formula
FORMULA:
Area of the triangle
\frac{1}{2} {x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)}
Step 3: Simplify further
NOTE: Apply the BODMAS rules
Method 2:
Step 1: Calculate the base and height lengths of the triangle
NOTE: Use the distance formula to calculate lengths.
Step 2: Substitute the either values (base and height lengths) in the formula
Area of the right angle triangle = \frac{1}{2} base * height
Step 3: Simplify further
NOTE: Apply the BODMAS rules